Question: Plot the circle $$(x-1)^2+(y-1)^2=9.$$ $$(x-2)^2+(y-2)^2=9$$
1. The problem is to plot the circle given by the equation $$(x-1)^2+(y-1)^2=9.$$
2. This is the equation of a circle in standard form: $$(x-h)^2+(y-k)^2=r^2,$$ where $(h,k)$ is the center and $r$ is the radius.
3. From the equation, the center is $(1,1)$ and the radius is $r=\sqrt{9}=3$.
4. To plot the circle, draw all points that are exactly $3$ units away from the center $(1,1)$.
5. The circle passes through points like $(1+3,1)=(4,1)$, $(1-3,1)=(-2,1)$, $(1,1+3)=(1,4)$, and $(1,1-3)=(1,-2)$.
6. The equation $$(x-2)^2+(y-2)^2=9$$ is a different circle with center $(2,2)$ and radius $3$, but the problem asks for the first circle.
Final answer: The circle has center $(1,1)$ and radius $3$.