1. **State the problem:** Find the area of the compound figure composed of rectangles and a semicircle with given side lengths. 2. **Identify parts of the figure:** The figure consists of two rectangles and a semicircle. 3. **Calculate the area of the top-right rectangle:** The rectangle has dimensions 9 yd (width) and 5 yd (height). $$\text{Area}_{\text{rect1}} = 9 \times 5 = 45 \text{ yd}^2$$ 4. **Calculate the area of the bottom-left rectangle:** The rectangle has dimensions 8 yd (width) and 2 yd (height). $$\text{Area}_{\text{rect2}} = 8 \times 2 = 16 \text{ yd}^2$$ 5. **Calculate the area of the semicircle:** The semicircle is attached to the bottom of the left rectangle. Its diameter equals the width of the bottom rectangle, which is 8 yd. Radius $r = \frac{8}{2} = 4$ yd. Area of full circle: $$\pi r^2 = \pi \times 4^2 = 16\pi$$ Area of semicircle: $$\frac{1}{2} \times 16\pi = 8\pi \approx 25.13 \text{ yd}^2$$ 6. **Sum all areas:** $$45 + 16 + 25.13 = 86.13 \text{ yd}^2$$ 7. **Final answer:** The area of the compound figure is approximately **86.13 square yards**.