Question: User: volume of a sphere = $\frac{4}{3} \pi r^3$ where $r$ is the radius.
The shape below is made from a cylinder and a hemisphere.
The total volume of this shape is $\frac{2684}{3} \pi$ cm$^3$
Work out the height of the cylinder.
Give your answer to 1 d.p.
Graph/shapes: A pink solid composed of a cylinder on top of a hemisphere, with a horizontal dimension arrow labeled "$8$ cm" across the top circular face. position_hint: bottom-center
1. **State the problem:** We have a solid made of a cylinder on top of a hemisphere. The total volume is given as $$\frac{2684}{3} \pi$$ cm$^3$. The radius $r$ of both the cylinder and hemisphere is $4$ cm (since diameter is $8$ cm). We need to find the height $h$ of the cylinder.
2. **Formulas:**
- Volume of a hemisphere: $$V_{hemisphere} = \frac{1}{2} \times \frac{4}{3} \pi r^3 = \frac{2}{3} \pi r^3$$
- Volume of a cylinder: $$V_{cylinder} = \pi r^2 h$$
- Total volume: $$V_{total} = V_{cylinder} + V_{hemisphere}$$
3. **Calculate the volume of the hemisphere:**
$$V_{hemisphere} = \frac{2}{3} \pi (4)^3 = \frac{2}{3} \pi \times 64 = \frac{128}{3} \pi$$
4. **Set up the equation for total volume:**
$$\pi r^2 h + \frac{128}{3} \pi = \frac{2684}{3} \pi$$
5. **Divide both sides by $\pi$ to simplify:**
$$r^2 h + \frac{128}{3} = \frac{2684}{3}$$
6. **Substitute $r=4$:**
$$16 h + \frac{128}{3} = \frac{2684}{3}$$
7. **Subtract $\frac{128}{3}$ from both sides:**
$$16 h = \frac{2684}{3} - \frac{128}{3} = \frac{2684 - 128}{3} = \frac{2556}{3}$$
8. **Simplify the right side:**
$$16 h = 852$$
9. **Divide both sides by 16:**
$$h = \frac{852}{16} = \frac{\cancel{852}^{53.25}}{\cancel{16}^{1}} = 53.25$$
10. **Round to 1 decimal place:**
$$h = 53.3 \text{ cm}$$
**Final answer:** The height of the cylinder is $53.3$ cm.