1. **State the problem:** Find the surface area of a cylinder with diameter 4.8 yd and height 2 yd. 2. **Formula:** The surface area $SA$ of a cylinder is given by $$SA = 2\pi r^2 + 2\pi r h$$ where $r$ is the radius and $h$ is the height. 3. **Find the radius:** The radius $r$ is half the diameter: $$r = \frac{4.8}{2} = 2.4 \text{ yd}$$ 4. **Calculate the areas:** - Area of the two circular bases: $$2\pi r^2 = 2 \times 3.14 \times (2.4)^2 = 2 \times 3.14 \times 5.76 = 36.1728$$ - Area of the side (lateral surface area): $$2\pi r h = 2 \times 3.14 \times 2.4 \times 2 = 30.144$$ 5. **Add the areas:** $$SA = 36.1728 + 30.144 = 66.3168$$ 6. **Round to nearest hundredth:** $$SA \approx 66.32 \text{ square yards}$$ **Final answer:** The surface area of the cylinder is **66.32 square yards**.