Subjects geometry

Distance Ab 874F2D

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Question: A centimetre square grid is shown below. Point A has coordinates $(1, 3)$ and point B has coordinates $(9, 8)$. Using Pythagoras' theorem, calculate the distance from $A$ to $B$. Give your answer to 1 d.p.
1. **State the problem:** We need to find the distance between points $A(1, 3)$ and $B(9, 8)$ on a coordinate grid. 2. **Formula:** The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by Pythagoras' theorem: $$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$ 3. **Calculate the differences:** $$x_2 - x_1 = 9 - 1 = 8$$ $$y_2 - y_1 = 8 - 3 = 5$$ 4. **Substitute into the formula:** $$d = \sqrt{8^2 + 5^2} = \sqrt{64 + 25} = \sqrt{89}$$ 5. **Evaluate the square root:** $$d \approx 9.433...$$ 6. **Round to 1 decimal place:** $$d \approx 9.4$$ **Final answer:** The distance from $A$ to $B$ is approximately $9.4$ units.
A(1,3)B(9,8)85