1. **State the problem:** We have a large triangle on a straight line base with angles 46°, 63°, y, 140°, and x as shown. We need to find the values of $x$ and $y$.
2. **Identify known angle relationships:** The straight line base means angles on the line sum to 180°.
3. **Use the straight line angle sum:** The angle adjacent to 140° on the straight line is $180° - 140° = 40°$. This angle is $x$ because it is the angle at the base where the interior segment meets the line.
4. **Use triangle angle sum rule:** The top vertex angle is split into two parts: 63° and $y$. The sum of angles in the triangle is 180°, so for the triangle with angles 46°, 63° + $y$, and the angle at the base where the segment meets the line (which is $x$), we have:
$$46° + (63° + y) + x = 180°$$
5. **Substitute $x = 40°$ from step 3:**
$$46° + 63° + y + 40° = 180°$$
6. **Simplify and solve for $y$:**
$$149° + y = 180°$$
$$y = 180° - 149° = 31°$$
**Final answers:**
$$x = 40°$$
$$y = 31°$$
Find X Y 9A1B06
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