Subjects geometry

Garden Path Length 45922C

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Question: A design for a circular garden is shown below. The paths bordering Section 1 meet at a right angle. The distance around the circular garden is 125.6 m. Three paths of equal length run from the centre of the circle to the edge. Section 2 and Section 3 have the same shape and area and are congruent Landscape Design Plan Design garden Section 1 Shrub Tree Section 2 Path Section 3 Flower bed Flower bed Flower bed Shrub Question 22 What is the length of each path in the landscape design plan? 6.323 m 19.99 m 39.98 m 41.87 m
1. **State the problem:** We have a circular garden with circumference $125.6$ m. Three paths of equal length run from the center to the edge, dividing the circle into three sections. Section 1 is bordered by paths meeting at a right angle ($90^\circ$). Sections 2 and 3 are congruent. 2. **Find the radius of the circle:** The circumference formula is $$C = 2\pi r$$ Given $$C = 125.6$$, solve for $$r$$: $$r = \frac{C}{2\pi} = \frac{125.6}{2 \times 3.14} = \frac{125.6}{6.28} = 20$$ m 3. **Analyze the angles:** Section 1 has an angle of $90^\circ$. The total circle is $360^\circ$. Sections 2 and 3 are congruent, so their angles are equal. Let each of these angles be $$x$$. 4. **Calculate the angles of Sections 2 and 3:** $$90 + x + x = 360$$ $$2x = 360 - 90 = 270$$ $$x = \frac{270}{2} = 135^\circ$$ 5. **Length of each path:** The paths run from the center to the edge, so each path is a radius. From step 2, the radius $$r = 20$$ m. 6. **Check the options:** The radius is $20$ m, closest to $19.99$ m. **Final answer:** The length of each path is approximately **$19.99$ m**.
Section 1 (90°)Section 2 (135°)Section 3 (135°)