Question: Find the area of the kite.
15 ft
6 ft
7 ft
6 ft
Shape: kite with diagonals crossing at the center; the horizontal diagonal is 15 ft + 7 ft = 22 ft, and the vertical diagonal is 6 ft + 6 ft = 12 ft, position_hint \in {center}.
? ft²
1. **State the problem:** We need to find the area of a kite given the lengths of its diagonals.
2. **Formula for the area of a kite:** The area $A$ of a kite is given by
$$A = \frac{1}{2} \times d_1 \times d_2$$
where $d_1$ and $d_2$ are the lengths of the diagonals.
3. **Identify the diagonals:** From the problem, the horizontal diagonal is $15 + 7 = 22$ ft and the vertical diagonal is $6 + 6 = 12$ ft.
4. **Calculate the area:**
$$A = \frac{1}{2} \times 22 \times 12$$
5. **Simplify the multiplication:**
$$A = \frac{1}{2} \times 264$$
6. **Simplify the fraction:**
$$A = \cancel{\frac{1}{2}} \times \cancel{264} = 132$$
7. **Final answer:** The area of the kite is $132$ square feet.