Question: Given that $E$ is the midpoint of $AD$ and $BC$, prove $AB \parallel CD$.
1. **Problem Statement:**
Given a quadrilateral $ABCD$ where $E$ is the midpoint of both $AD$ and $BC$, prove that the line segments $AB$ and $CD$ are parallel.
2. **Key Concept:**
If a line segment joining the midpoints of two sides of a quadrilateral is parallel to the other two sides, then those sides are parallel.
3. **Step 1: Define Midpoints**
Since $E$ is the midpoint of $AD$, we have:
$$E = \frac{A + D}{2}$$
Similarly, since $E$ is the midpoint of $BC$, we have:
$$E = \frac{B + C}{2}$$
4. **Step 2: Equate Midpoints**
From the above, we get:
$$\frac{A + D}{2} = \frac{B + C}{2}$$
Multiply both sides by 2:
$$A + D = B + C$$
5. **Step 3: Rearrange to find vector relation**
Rearranging:
$$A - B = C - D$$
This means the vector from $B$ to $A$ is equal to the vector from $D$ to $C$:
$$\overrightarrow{AB} = \overrightarrow{DC}$$
6. **Step 4: Conclusion**
Since $\overrightarrow{AB}$ and $\overrightarrow{DC}$ are equal vectors, they have the same direction and magnitude.
Therefore, the line segments $AB$ and $CD$ are parallel and equal in length.
**Final answer:**
$$AB \parallel CD$$