Question: Name the minor arc and find its measure. A D B C 115° ⌢ADB 30 ⌢AB 115 ⌢ADB 245 ⌢AB 245 13 Multiple Choice 1 point Find x in circle O. (The figure is not drawn to scale.) A B C O 41° x° 82 20.5 49 top-center: circle diagram with center C, radii CA and CB forming a 115° central angle; position of the minor arc is A to B on the right side of the circle, and the intended arc-measure answer is 115°. center: second circle diagram labeled O with points A, B, C on the circumference; angle x is at A between chords/segments AB and AC, and arc BC is marked 41° near the bottom, with a likely relation x = 20.5° from the inscribed angle theorem.

1. **Problem 1: Name the minor arc and find its measure.** Given a circle with center C and points A and B on the circumference, the central angle $\angle ACB$ measures $$115^\circ$$. - The minor arc is the arc intercepted by the central angle, which is the arc from A to B, denoted as $$\widehat{AB}$$. - Since the central angle measures $$115^\circ$$, the measure of the minor arc $$\widehat{AB}$$ is also $$115^\circ$$. **Answer:** The minor arc is $$\widehat{AB}$$ and its measure is $$115^\circ$$. 2. **Problem 2: Find $x$ in circle O.** Given: - Circle with center O. - Points A, B, C on the circumference. - Arc $$\widehat{BC}$$ measures $$41^\circ$$. - Angle $x$ is an inscribed angle at point A intercepting arc $$\widehat{BC}$$. **Step 1:** Recall the inscribed angle theorem: $$x = \frac{1}{2} \times \text{measure of intercepted arc}$$ **Step 2:** Substitute the given arc measure: $$x = \frac{1}{2} \times 41^\circ$$ **Step 3:** Calculate: $$x = 20.5^\circ$$ **Answer:** $$x = 20.5^\circ$$.