Question: Finding angles made by a tra... 3 of 4 questions Below are two parallel lines with a third line intersecting them. 132° x° x = □ ° top-left: a pair of parallel diagonal lines run from upper-left to lower-right, intersected by a third diagonal line rising from lower-left to upper-right; at the lower-left intersection a blue arc labels 132° above the crossing, and at the upper-right intersection a green arc labels x° above the crossing.

1. **State the problem:** We have two parallel lines intersected by a transversal. One angle is given as $132^\circ$ and we need to find the value of angle $x^\circ$ formed at the other intersection. 2. **Recall the rule:** When a transversal crosses two parallel lines, alternate interior angles are equal. 3. **Identify the angles:** The angle labeled $132^\circ$ and the angle $x^\circ$ are alternate interior angles. 4. **Apply the rule:** Since the lines are parallel, $x = 132^\circ$. 5. **Final answer:** $$x = 132^\circ$$ This means the angle $x$ is equal to $132$ degrees because alternate interior angles are congruent when lines are parallel.