Question: The floor of a house is shaped like a parallelogram. The height of the parallelogram is 8 ft less than the base. The base is 48 ft. The length of the other side of the parallelogram is 45 ft.
What is the area of the floor?
88 ft²
133 ft²
1,920 ft²
2,160 ft²
1. **State the problem:** We need to find the area of a parallelogram-shaped floor where the base is $48$ ft and the height is $8$ ft less than the base.
2. **Recall the formula for the area of a parallelogram:**
$$\text{Area} = \text{base} \times \text{height}$$
3. **Identify given values:**
- Base $b = 48$ ft
- Height $h = b - 8 = 48 - 8 = 40$ ft
4. **Calculate the area:**
$$\text{Area} = 48 \times 40$$
5. **Multiply:**
$$48 \times 40 = 1920$$
6. **Interpretation:** The area of the floor is $1920$ square feet.
7. **Note:** The length of the other side ($45$ ft) is not needed to find the area since the area depends only on base and height.
**Final answer:** $1920$ ft²