Question: Use this parallelogram to answer the question.
7.5 in.
3.5 in.
10 in.
6 in.
What is the area of the parallelogram?
9.5 in.^2
11 in.^2
21 in.^2
26.25 in.^2
Graph shape: a slanted parallelogram is shown in the top-left area, with a dashed diagonal from the bottom-left vertex to the top-right vertex, a base labeled 3.5 in. along the bottom, a slanted side labeled 7.5 in. on the left, an interior diagonal labeled 10 in., and a vertical height on the right labeled 6 in.; position_hint=top-left
1. **State the problem:** We need to find the area of a parallelogram with given dimensions: base $3.5$ in. and height $6$ in.
2. **Formula for area of a parallelogram:**
$$\text{Area} = \text{base} \times \text{height}$$
3. **Identify the base and height:**
The base is given as $3.5$ in., and the height (the perpendicular distance between the bases) is $6$ in.
4. **Calculate the area:**
$$\text{Area} = 3.5 \times 6$$
$$= 21$$
5. **Interpretation:** The area of the parallelogram is $21$ square inches.
**Final answer:** $21$ in.$^2$