1. **State the problem:** (i) Find the volume of a spherical ice cube of radius 1.5 cm in terms of $\pi$. (ii) Find the rise $h$ cm in the water level when three such ice cubes are submerged in a cylinder of radius 3.5 cm. 2. **Formula for volume of a sphere:** $$V = \frac{4}{3} \pi r^3$$ where $r$ is the radius. 3. **Calculate volume of one spherical ice cube:** $$V = \frac{4}{3} \pi (1.5)^3$$ $$= \frac{4}{3} \pi (3.375)$$ $$= \frac{4 \times 3.375}{3} \pi$$ $$= \frac{13.5}{3} \pi = 4.5 \pi$$ 4. **Check given answer:** The user states $V = \frac{9}{2} \pi$ which equals $4.5 \pi$, so this matches. 5. **Volume of three ice cubes:** $$3 \times 4.5 \pi = 13.5 \pi$$ 6. **Formula for volume of cylinder segment:** $$V = \pi r^2 h$$ where $r$ is radius of cylinder and $h$ is height of water rise. 7. **Set volume of displaced water equal to volume of ice cubes:** $$\pi (3.5)^2 h = 13.5 \pi$$ 8. **Simplify by canceling $\pi$:** $$\cancel{\pi} (3.5)^2 h = 13.5 \cancel{\pi}$$ $$12.25 h = 13.5$$ 9. **Solve for $h$:** $$h = \frac{13.5}{12.25}$$ $$h \approx 1.102$$ 10. **Round to 1 decimal place:** $$h \approx 1.1$$ cm **Final answers:** (i) Volume of one spherical ice cube: $$\frac{9}{2} \pi$$ cm$^3$ (ii) Rise in water level: $$1.1$$ cm