Sum Interior Angles 77278B

1. **State the problem:** We need to find the sum of the interior angles of a polygon. 2. **Formula:** The sum of the interior angles of a polygon with $n$ sides is given by: $$\text{Sum of interior angles} = (n - 2) \times 180^\circ$$ 3. **Explanation:** This formula works because any polygon can be divided into $(n-2)$ triangles, and each triangle has interior angles summing to $180^\circ$. 4. **Apply the formula:** To find the sum, we need to know the number of sides $n$ of the polygon. Since the polygon is not described or shown here, we cannot calculate a numeric answer without $n$. 5. **Conclusion:** If you provide the number of sides $n$, we can calculate the sum as $(n - 2) \times 180^\circ$. **Example:** For a pentagon ($n=5$), the sum is $(5 - 2) \times 180^\circ = 3 \times 180^\circ = 540^\circ$.