Question: ∠1 and ∠2 are supplementary angles. If m∠1 = (3x + 27)° and m∠2 = (8x + 21)°, then find the measure of ∠1.
1. **State the problem:** We are given two supplementary angles ∠1 and ∠2 with measures m∠1 = $3x + 27$ degrees and m∠2 = $8x + 21$ degrees. We need to find the measure of ∠1.
2. **Recall the rule for supplementary angles:** Supplementary angles add up to $180^\circ$. So,
$$m\angle 1 + m\angle 2 = 180$$
3. **Set up the equation:** Substitute the given expressions:
$$ (3x + 27) + (8x + 21) = 180 $$
4. **Combine like terms:**
$$ 3x + 8x + 27 + 21 = 180 $$
$$ 11x + 48 = 180 $$
5. **Isolate $x$:**
$$ 11x = 180 - 48 $$
$$ 11x = 132 $$
6. **Divide both sides by 11:**
$$ x = \frac{132}{11} $$
$$ x = \cancel{\frac{132}{11}} 12 $$
7. **Find m∠1:** Substitute $x=12$ into $3x + 27$:
$$ m\angle 1 = 3(12) + 27 = 36 + 27 = 63 $$
**Final answer:** The measure of ∠1 is $63^\circ$.