Question: Shape X' is a translation of shape X by 3 units to the right and 1 unit down.
What were the coordinates of point R?
1. **State the problem:**
We know that shape X' is a translation of shape X by 3 units to the right and 1 unit down.
We are given the coordinates of point R' on shape X' as approximately $$(5, 4)$$.
We need to find the original coordinates of point R on shape X.
2. **Recall the translation rule:**
If a point $$(x, y)$$ is translated by $$a$$ units to the right and $$b$$ units down, the new coordinates become $$(x + a, y - b)$$.
3. **Apply the rule in reverse:**
Since point R' is the image of point R after translation,
$$R' = (x + 3, y - 1)$$ where $$(x, y)$$ are the coordinates of point R.
4. **Set up equations:**
Given $$R' = (5, 4)$$,
we have:
$$x + 3 = 5$$
$$y - 1 = 4$$
5. **Solve for $$x$$ and $$y$$:**
$$x = 5 - 3 = 2$$
$$y = 4 + 1 = 5$$
6. **Conclusion:**
The original coordinates of point R are $$(2, 5)$$.