1. **State the problem:** We need to find the area of a trapezoid with parallel sides (bases) of lengths 3 and 10, a height of 24, and a slanted side of length 25. 2. **Formula for the area of a trapezoid:** $$\text{Area} = \frac{(\text{base}_1 + \text{base}_2)}{2} \times \text{height}$$ 3. **Identify the bases and height:** - Base 1 ($b_1$) = 3 - Base 2 ($b_2$) = 10 - Height ($h$) = 24 4. **Calculate the area:** $$\text{Area} = \frac{(3 + 10)}{2} \times 24 = \frac{13}{2} \times 24 = 6.5 \times 24$$ 5. **Multiply:** $$6.5 \times 24 = 156$$ 6. **Final answer:** The area of the trapezoid is $156$ square units.