1. **State the problem:** We need to find the area of a trapezoid with one pair of parallel sides (bases) measuring 6 and 8 units, and a height of 5 units. 2. **Formula for the area of a trapezoid:** $$\text{Area} = \frac{(\text{Base}_1 + \text{Base}_2)}{2} \times \text{Height}$$ 3. **Apply the values:** $$\text{Area} = \frac{(6 + 8)}{2} \times 5$$ 4. **Simplify inside the parentheses:** $$6 + 8 = 14$$ 5. **Calculate the average of the bases:** $$\frac{14}{2} = 7$$ 6. **Multiply by the height:** $$7 \times 5 = 35$$ 7. **Final answer:** The area of the trapezoid is **35 square units**.