Question: In the given figure, which triangle has a greater area: $\triangle XDC$ or $\triangle YDC$, if both the rectangles are identical?
1. **State the problem:** We need to compare the areas of triangles $\triangle XDC$ and $\triangle YDC$ formed inside two identical rectangles.
2. **Understand the figure and given information:** Both rectangles are identical, meaning they have the same length and width.
3. **Recall the formula for the area of a triangle:**
$$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$
4. **Identify the base and height for both triangles:**
- Both triangles share the same base $DC$ (the bottom side of the rectangle).
- The height is the perpendicular distance from the opposite vertex ($X$ or $Y$) to the base $DC$.
5. **Analyze the positions of points $X$ and $Y$:**
- $X$ is near the left of the center on the top side of the left rectangle.
- $Y$ is at the center on the top side of the right rectangle.
6. **Since both rectangles are identical, their top sides are equal in length and parallel to $DC$.**
- The height for both triangles is the same because the top side is parallel and at the same distance from $DC$.
7. **Compare the bases of the triangles:**
- The base for both triangles is the segment $DC$, which is the same length in both rectangles.
8. **Check the horizontal segments forming the triangles:**
- $\triangle XDC$ is formed by points $X$, $D$, and $C$.
- $\triangle YDC$ is formed by points $Y$, $D$, and $C$.
9. **Since $X$ is closer to $D$ than $Y$ is, the horizontal projection of $X$ onto $DC$ is shorter than that of $Y$.**
10. **Calculate the area of each triangle:**
- Area of $\triangle XDC = \frac{1}{2} \times DC \times h_X$
- Area of $\triangle YDC = \frac{1}{2} \times DC \times h_Y$
11. **Because the height $h$ is the same for both triangles (distance from top side to $DC$), the difference in area depends on the horizontal position of $X$ and $Y$.**
12. **However, both triangles share the same base $DC$ and height (rectangle height), so their areas are equal.**
**Final answer:**
$$\boxed{\text{The areas of } \triangle XDC \text{ and } \triangle YDC \text{ are equal.}}$$