Subjects geometry

Triangle Area F66021

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Question: What is the area of the triangle below?
1. **State the problem:** We need to find the area of a triangle given its vertices. 2. **Formula:** The area of a triangle with vertices at coordinates $(x_1,y_1)$, $(x_2,y_2)$, and $(x_3,y_3)$ is given by: $$\text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|$$ 3. **Identify vertices:** From the description, the triangle vertices are approximately: - Top-left: $(0,2)$ - Bottom-left: $(0,0)$ - Right-center: $(3,1)$ 4. **Calculate area:** Substitute into the formula: $$\text{Area} = \frac{1}{2} |0(0 - 1) + 0(1 - 2) + 3(2 - 0)|$$ $$= \frac{1}{2} |0 + 0 + 3 \times 2| = \frac{1}{2} |6| = 3$$ 5. **Interpretation:** The area of the triangle is $3$ square units. **Final answer:** $3$ units²
A(0,2)B(0,0)C(3,1)