Question: Given that $SQ$ bisects $\angle PSR$ and $\angle SPQ \cong \angle SRQ$, prove $PS \cong SR$.
1. **State the problem:** We are given that $SQ$ bisects $\angle PSR$ and that $\angle SPQ \cong \angle SRQ$. We need to prove that $PS \cong SR$.
2. **Understand the given information:**
- $SQ$ bisects $\angle PSR$ means $\angle PSQ = \angle QSR$.
- $\angle SPQ \cong \angle SRQ$ means these two angles are equal.
3. **Identify triangles to compare:** Consider triangles $PSQ$ and $RSQ$.
4. **List known equal parts:**
- $SQ$ is common side to both triangles.
- $\angle PSQ = \angle QSR$ (since $SQ$ bisects $\angle PSR$).
- $\angle SPQ = \angle SRQ$ (given).
5. **Apply Angle-Angle-Side (AAS) congruence criterion:**
- Two angles and the non-included side are equal in both triangles.
6. **Conclude triangles are congruent:**
$$\triangle PSQ \cong \triangle RSQ$$
7. **Therefore, corresponding sides are equal:**
$$PS \cong SR$$
**Final answer:** $PS \cong SR$ as required.