Subjects geometry

Triangle Reflection 5B536B

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Question: Reflect the figure over the line $x = -1$. Plot all of the points of the reflected figure. You may click a plotted point to delete it. Graph shape: a triangle in the bottom-right of the coordinate plane with vertices at $(1, -2)$, $(4, -3)$, and $(1, -8)$; reflect it across $x = -1$.
1. **State the problem:** We need to reflect a triangle with vertices at $ (1, -2)$, $ (4, -3)$, and $ (1, -8)$ across the vertical line $x = -1$. 2. **Reflection formula:** When reflecting a point $ (x, y)$ across the vertical line $x = a$, the reflected point $ (x', y')$ is given by: $$x' = 2a - x, \quad y' = y$$ 3. **Apply the formula to each vertex:** - For $ (1, -2)$: $$x' = 2(-1) - 1 = -2 - 1 = -3, \quad y' = -2$$ - For $ (4, -3)$: $$x' = 2(-1) - 4 = -2 - 4 = -6, \quad y' = -3$$ - For $ (1, -8)$: $$x' = 2(-1) - 1 = -3, \quad y' = -8$$ 4. **Reflected vertices:** The reflected triangle has vertices at: $$(-3, -2), (-6, -3), (-3, -8)$$ 5. **Explanation:** Each point is mirrored across the line $x = -1$ by calculating the horizontal distance from the point to the line and placing the reflected point the same distance on the opposite side. **Final answer:** The reflected triangle vertices are $(-3, -2)$, $(-6, -3)$, and $(-3, -8)$.
(1,-2)(4,-3)(1,-8)(-3,-2)(-6,-3)(-3,-8)