Question: User: Statements 1 and 2 are true conditional statements.
Statement 1: If a figure is a square, then it is a rectangle.
Statement 2: If a figure is a rectangle, then it is a parallelogram.
Which conclusion is valid?
A If Figure A is a square, then Figure A is a parallelogram. position_hint: bottom-left
B If Figure A is not a square, then Figure A is not a parallelogram. position_hint: bottom-right
C If Figure A is a parallelogram, then Figure A is a square. position_hint: bottom-left
D If Figure A is a rectangle, then Figure A is a square. position_hint: bottom-right
1. **State the problem:** We have two true conditional statements:
- Statement 1: If a figure is a square, then it is a rectangle.
- Statement 2: If a figure is a rectangle, then it is a parallelogram.
We want to determine which conclusion among A, B, C, and D is valid.
2. **Recall the rule of transitivity for conditional statements:**
If $P \to Q$ and $Q \to R$ are true, then $P \to R$ is also true.
3. **Apply the rule:**
Let:
- $P$: Figure A is a square.
- $Q$: Figure A is a rectangle.
- $R$: Figure A is a parallelogram.
Given:
- $P \to Q$ (Statement 1)
- $Q \to R$ (Statement 2)
By transitivity:
$$P \to R$$
This means: If Figure A is a square, then Figure A is a parallelogram.
4. **Evaluate the options:**
- A: If Figure A is a square, then Figure A is a parallelogram. **Valid** (matches $P \to R$).
- B: If Figure A is not a square, then Figure A is not a parallelogram. **Invalid** (the contrapositive of $P \to R$ is If not $R$, then not $P$, not this).
- C: If Figure A is a parallelogram, then Figure A is a square. **Invalid** (reverse of $P \to R$, not necessarily true).
- D: If Figure A is a rectangle, then Figure A is a square. **Invalid** (reverse of $P \to Q$, not necessarily true).
5. **Final answer:** The valid conclusion is option A.
**Answer:** A. If Figure A is a square, then Figure A is a parallelogram.