Question: User: answer should be 6.3 ft/s^2
1. The problem is to verify or find the acceleration value given as $6.3\ \text{ft/s}^2$.
2. Acceleration is defined as the rate of change of velocity with respect to time, mathematically expressed as $$a = \frac{\Delta v}{\Delta t}$$ where $a$ is acceleration, $\Delta v$ is change in velocity, and $\Delta t$ is change in time.
3. To confirm the acceleration value, you need the initial and final velocities and the time interval over which the change occurs.
4. If the problem states or implies the acceleration is $6.3\ \text{ft/s}^2$, then this is the acceleration value.
5. Without additional data, the answer is simply the stated acceleration: $$6.3\ \text{ft/s}^2$$.