Power Between Xy 6A3Dfe

1. **Problem Statement:** We have a 9V battery connected to two resistors, $1000\Omega$ and $3000\Omega$, in series. The battery current is $3\text{mA}$, and the current drawn from terminals X and Y is $1\text{mA}$. We need to find the power supplied to the circuit connected between X and Y. 2. **Understanding the circuit:** The battery current $I_{battery} = 3\text{mA}$ flows through the $1000\Omega$ resistor. At node X, $1\text{mA}$ current is drawn by the external circuit connected between X and Y. The remaining current $2\text{mA}$ flows through the $3000\Omega$ resistor. 3. **Calculate voltage at terminal X:** - Voltage drop across the $1000\Omega$ resistor is given by Ohm's law: $$ V_{1000} = I_{battery} \times R = 3\times10^{-3} \times 1000 = 3\text{V} $$ - Since the battery voltage is $9\text{V}$, voltage at terminal X is: $$ V_X = 9 - V_{1000} = 9 - 3 = 6\text{V} $$ 4. **Voltage at terminal Y:** Terminal Y is connected after the $3000\Omega$ resistor, which is connected to ground (0V), so: $$ V_Y = 0\text{V} $$ 5. **Voltage across the circuit connected between X and Y:** $$ V_{XY} = V_X - V_Y = 6 - 0 = 6\text{V} $$ 6. **Current through the circuit connected between X and Y:** $$ I_{XY} = 1\text{mA} = 1 \times 10^{-3} \text{A} $$ 7. **Calculate power supplied to the circuit between X and Y:** $$ P = V_{XY} \times I_{XY} = 6 \times 1 \times 10^{-3} = 6 \times 10^{-3} = 0.006\text{W} = 6\text{mW} $$ **Final answer:** The power supplied to the circuit connected between X and Y is **6mW**. **Answer choice:** A