Question: A formula connecting speed $s$, distance $d$ and time $t$ is
$s = \frac{d}{t}$
d = 180 metres to 2 significant figures
t = 7.2 seconds to 2 significant figures
Calculate the lower and upper bounds of $s$.
Give your answers to 3 significant figures.
1. **State the problem:**
We need to find the lower and upper bounds of speed $s$ given $d = 180$ metres (2 significant figures) and $t = 7.2$ seconds (2 significant figures) using the formula $s = \frac{d}{t}$.
2. **Understand bounds for $d$ and $t$:**
- For $d = 180$ (2 s.f.), the lower bound is $180 - 0.5 \times 10^{3-2} = 180 - 5 = 175$ metres.
- The upper bound is $180 + 5 = 185$ metres.
- For $t = 7.2$ (2 s.f.), the lower bound is $7.2 - 0.05 = 7.15$ seconds.
- The upper bound is $7.2 + 0.05 = 7.25$ seconds.
3. **Calculate lower bound of $s$:**
Speed is lowest when distance is minimum and time is maximum:
$$s_{lower} = \frac{d_{lower}}{t_{upper}} = \frac{175}{7.25} \approx 24.138$$
Rounded to 3 significant figures: $24.1$ m/s.
4. **Calculate upper bound of $s$:**
Speed is highest when distance is maximum and time is minimum:
$$s_{upper} = \frac{d_{upper}}{t_{lower}} = \frac{185}{7.15} \approx 25.874$$
Rounded to 3 significant figures: $25.9$ m/s.
5. **Final answer:**
The lower bound of speed $s$ is $24.1$ m/s and the upper bound is $25.9$ m/s.