Question: Determine the x- and y-components of the ball's velocity at t = 2.0 s.
1. **State the problem:** We need to find the x- and y-components of the velocity of a ball at time $t = 2.0$ seconds.
2. **Identify the formulas:**
- The velocity in the x-direction, $v_x$, is usually constant if no horizontal acceleration is present.
- The velocity in the y-direction, $v_y$, changes due to gravity and is given by $$v_y = v_{y0} - g t$$ where $v_{y0}$ is the initial vertical velocity, $g$ is the acceleration due to gravity (approximately $9.8$ m/s$^2$), and $t$ is time.
3. **Assumptions:**
- If initial velocities are not given, assume initial horizontal velocity $v_{x0}$ and initial vertical velocity $v_{y0}$ are known or given.
4. **Calculate $v_x$:**
- Since horizontal velocity is constant, $$v_x = v_{x0}$$
5. **Calculate $v_y$:**
- Using the formula $$v_y = v_{y0} - g t$$
- Substitute $t = 2.0$ s and $g = 9.8$ m/s$^2$.
6. **Final answer:**
- The x-component of velocity at $t=2.0$ s is $$v_x = v_{x0}$$
- The y-component of velocity at $t=2.0$ s is $$v_y = v_{y0} - 9.8 \times 2.0 = v_{y0} - 19.6$$
If you provide the initial velocities, I can calculate numerical values.