Question: User: AL Bataeh (UAE) vs FC Palm City
United Arab Emirates - Presidents Cup
23/09/2026 14:40
ODDS DELAYED 30 MIN Log in for live odds
Markets
MAIN
OTHER
Teams To Score
Team Total Home
Team Total Away
Spread H
Lines (8)
Over/Under +1.5 35 2.35 1.53
Over/Under +0.5 13 1.28 3.14
Over/Under +1 9 1.55 2.25
Over/Under +2 6 4.40 1.16
Over/Under +2.5 12 5.40 1.10
Over/Under +3.5 2 10.00 1.00
Over/Under +4.5 2 16.00 1.00
graph: a vertical list/table of seven over/under betting lines with two odds buttons on the right of each row; position_hint = center
One divided by each line over and under and after add them together
1. **State the problem:** We are given seven over/under betting lines with odds for "over" and "under" outcomes. We need to calculate the sum of the reciprocals of each "over" and "under" odd for all lines.
2. **Formula:** For each line with odds $O_{over}$ and $O_{under}$, calculate $\frac{1}{O_{over}} + \frac{1}{O_{under}}$. Then sum these values for all lines.
3. **Calculate each line:**
- Line 1 (Over/Under +1.5): $\frac{1}{2.35} + \frac{1}{1.53} = 0.4255 + 0.6536 = 1.0791$
- Line 2 (Over/Under +0.5): $\frac{1}{1.28} + \frac{1}{3.14} = 0.7813 + 0.3185 = 1.0998$
- Line 3 (Over/Under +1): $\frac{1}{1.55} + \frac{1}{2.25} = 0.6452 + 0.4444 = 1.0896$
- Line 4 (Over/Under +2): $\frac{1}{4.40} + \frac{1}{1.16} = 0.2273 + 0.8621 = 1.0894$
- Line 5 (Over/Under +2.5): $\frac{1}{5.40} + \frac{1}{1.10} = 0.1852 + 0.9091 = 1.0943$
- Line 6 (Over/Under +3.5): $\frac{1}{10.00} + \frac{1}{1.00} = 0.1000 + 1.0000 = 1.1000$
- Line 7 (Over/Under +4.5): $\frac{1}{16.00} + \frac{1}{1.00} = 0.0625 + 1.0000 = 1.0625$
4. **Sum all results:**
$$
1.0791 + 1.0998 + 1.0896 + 1.0894 + 1.0943 + 1.1000 + 1.0625 = 7.6147
$$
5. **Conclusion:** The sum of the reciprocals of the odds for all seven lines is approximately $7.6147$.