Question: What fraction of times did the spinner land on either blue or yellow? Give your answer in its simplest form.
Blue
$\frac{3}{7}$
Green
$\frac{2}{7}$
Red
$\frac{1}{7}$
Yellow
$\frac{1}{7}$
1. **State the problem:** We need to find the fraction of times the spinner lands on either blue or yellow.
2. **Identify the fractions:** The spinner lands on blue with probability $\frac{3}{7}$ and on yellow with probability $\frac{1}{7}$.
3. **Add the fractions:** Since these are mutually exclusive events, we add the fractions:
$$\frac{3}{7} + \frac{1}{7} = \frac{3+1}{7} = \frac{4}{7}$$
4. **Simplify the fraction:** The fraction $\frac{4}{7}$ is already in simplest form because 4 and 7 have no common factors other than 1.
**Final answer:** The spinner lands on either blue or yellow $\frac{4}{7}$ of the time.