Question: Use the given frequency distribution to find the
(a) class width.
(b) class midpoints.
(c) class boundaries.
Temperature (°F) Frequency
50-53 1
54-57 3
58-61 5
62-65 11
66-69 7
70-73 7
74-77 1
(c) What are the class boundaries? Complete the table below. (Type integers or decimals.)
Temperature (°F) Frequency Class boundaries
50-53 1
54-57 3
58-61 5
62-65 11
66-69 7
70-73 7
74-77 1
1. **State the problem:** We are given a frequency distribution with temperature classes and frequencies. We need to find:
(a) Class width
(b) Class midpoints
(c) Class boundaries
2. **Find the class width:**
The class width is the difference between the lower limits of two consecutive classes.
For example, between the first two classes:
$$54 - 50 = 4$$
So, the class width is $4$.
3. **Find the class midpoints:**
The midpoint of a class is the average of the lower and upper class limits.
Formula:
$$\text{Midpoint} = \frac{\text{Lower limit} + \text{Upper limit}}{2}$$
Calculate for each class:
- $\frac{50 + 53}{2} = \frac{103}{2} = 51.5$
- $\frac{54 + 57}{2} = \frac{111}{2} = 55.5$
- $\frac{58 + 61}{2} = \frac{119}{2} = 59.5$
- $\frac{62 + 65}{2} = \frac{127}{2} = 63.5$
- $\frac{66 + 69}{2} = \frac{135}{2} = 67.5$
- $\frac{70 + 73}{2} = \frac{143}{2} = 71.5$
- $\frac{74 + 77}{2} = \frac{151}{2} = 75.5$
4. **Find the class boundaries:**
Class boundaries are the values that separate classes without gaps.
Since classes are continuous and the upper limit of one class is $53$ and the next class starts at $54$, the boundary is the midpoint between $53$ and $54$:
$$\frac{53 + 54}{2} = 53.5$$
Similarly, for other boundaries:
- Between $57$ and $58$: $\frac{57 + 58}{2} = 57.5$
- Between $61$ and $62$: $\frac{61 + 62}{2} = 61.5$
- Between $65$ and $66$: $\frac{65 + 66}{2} = 65.5$
- Between $69$ and $70$: $\frac{69 + 70}{2} = 69.5$
- Between $73$ and $74$: $\frac{73 + 74}{2} = 73.5$
Now, the class boundaries for each class are:
- First class: lower boundary = $49.5$ (one half less than $50$), upper boundary = $53.5$
- Second class: $53.5$ to $57.5$
- Third class: $57.5$ to $61.5$
- Fourth class: $61.5$ to $65.5$
- Fifth class: $65.5$ to $69.5$
- Sixth class: $69.5$ to $73.5$
- Seventh class: $73.5$ to $77.5$ (one half more than $77$)
5. **Complete the table with class boundaries:**
| Temperature (°F) | Frequency | Class Boundaries |
|------------------|-----------|------------------|
| 50-53 | 1 | 49.5 - 53.5 |
| 54-57 | 3 | 53.5 - 57.5 |
| 58-61 | 5 | 57.5 - 61.5 |
| 62-65 | 11 | 61.5 - 65.5 |
| 66-69 | 7 | 65.5 - 69.5 |
| 70-73 | 7 | 69.5 - 73.5 |
| 74-77 | 1 | 73.5 - 77.5 |
**Final answers:**
- (a) Class width = $4$
- (b) Class midpoints = $51.5, 55.5, 59.5, 63.5, 67.5, 71.5, 75.5$
- (c) Class boundaries as in the table above.