Question: The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has a bell-shaped distribution. This distribution has a mean of $55$ and a standard deviation of $3$. Using the empirical rule, what is the approximate percentage of 1-mile long roadways with potholes numbering between $46$ and $61$?
1. **State the problem:** We want to find the approximate percentage of 1-mile long roadways with potholes numbering between $46$ and $61$ given a normal distribution with mean $\mu=55$ and standard deviation $\sigma=3$.
2. **Recall the empirical rule:** For a bell-shaped (normal) distribution, about 68% of data lies within $1$ standard deviation of the mean, about 95% lies within $2$ standard deviations, and about 99.7% lies within $3$ standard deviations.
3. **Calculate the number of standard deviations from the mean for the bounds:**
- Lower bound: $46$
- Upper bound: $61$
Calculate the z-scores:
$$ z_{lower} = \frac{46 - 55}{3} = \frac{-9}{3} = -3 $$
$$ z_{upper} = \frac{61 - 55}{3} = \frac{6}{3} = 2 $$
4. **Interpret the interval:** The interval $[46,61]$ corresponds to $[-3,2]$ standard deviations from the mean.
5. **Use the empirical rule:**
- About 95% of data lies between $-2$ and $2$ standard deviations.
- About 99.7% lies between $-3$ and $3$ standard deviations.
Since our interval is from $-3$ to $2$, it covers slightly more than 95% but less than 99.7%.
6. **Estimate the percentage:**
- From $-2$ to $2$ is about 95%.
- From $-3$ to $-2$ is about 2.35% (half of the 0.3% outside $\pm 3$ SD is split evenly, so about 0.15% beyond $-3$ and 2.35% between $-3$ and $-2$).
So the total percentage between $-3$ and $2$ is approximately $95\% + 2.35\% = 97.35\%$.
**Final answer:** Approximately $97$ percent of 1-mile long roadways have potholes numbering between $46$ and $61$.