Question: User: Weight Away, a company that sells weight-loss plans, often advertises the effectiveness of its plans by highlighting the stories of a few clients who have lost extraordinary amounts of weight. The following gives information about more "typical" clients, summarizing the weight loss (in pounds) over the past month for a of 50 clients.
Based on the histogram, find the proportion of weight loss values in the sample that are at least 10 pounds. Write your answer as a decimal, and do not round your answer.
1. **State the problem:** We have a sample of 50 clients and their weight loss amounts over the past month. We want to find the proportion of clients who lost at least 10 pounds.
2. **Understand the data:** The histogram summarizes weight loss values for 50 clients. "At least 10 pounds" means weight loss values $\geq 10$.
3. **Find the number of clients with weight loss $\geq 10$:** From the histogram (not shown here), count the number of clients in the bins representing weight loss $\geq 10$ pounds.
4. **Calculate the proportion:**
$$\text{Proportion} = \frac{\text{Number of clients with weight loss } \geq 10}{50}$$
5. **Write the answer as a decimal without rounding.**
Since the histogram data is not provided explicitly, assume the number of clients with weight loss $\geq 10$ is $n$. Then the proportion is:
$$\frac{n}{50}$$
This fraction as a decimal is the exact proportion.
**Final answer:** The proportion of weight loss values at least 10 pounds is $\frac{n}{50}$ as a decimal, where $n$ is the count from the histogram.