Question: Find the exact value of $\sin(\frac{\pi}{4})$
1. **State the problem:** We need to find the exact value of $\sin\left(\frac{\pi}{4}\right)$.
2. **Recall the formula and important rules:** The angle $\frac{\pi}{4}$ radians is equivalent to $45^\circ$. The sine of $45^\circ$ is a well-known value from the unit circle and special right triangles.
3. **Use the special right triangle:** A $45^\circ-45^\circ-90^\circ$ triangle has sides in the ratio $1:1:\sqrt{2}$. The sine of $45^\circ$ is the ratio of the opposite side to the hypotenuse.
4. **Calculate the sine:**
$$\sin\left(\frac{\pi}{4}\right) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{1}{\sqrt{2}}.$$
5. **Rationalize the denominator:**
$$\sin\left(\frac{\pi}{4}\right) = \frac{1}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}.$$
6. **Final answer:**
$$\sin\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}.$$