Question: User: y=1-3\sin2\left(x+\frac{\pi}{3}\right)
1. **State the problem:** We are given the function $$y=1-3\sin2\left(x+\frac{\pi}{3}\right)$$ and we want to analyze it.
2. **Formula and explanation:** This is a sinusoidal function of the form $$y = A - B \sin(C(x+D))$$ where:
- $$A=1$$ is the vertical shift,
- $$B=3$$ is the amplitude,
- $$C=2$$ affects the period,
- $$D=\frac{\pi}{3}$$ is the horizontal phase shift.
3. **Period calculation:** The period $$T$$ of $$\sin(Cx)$$ is $$\frac{2\pi}{C}$$.
$$T = \frac{2\pi}{2} = \pi$$
4. **Amplitude:** The amplitude is the absolute value of the coefficient in front of sine:
$$|B| = 3$$
5. **Phase shift:** The phase shift is given by $$-D$$:
$$-\frac{\pi}{3}$$ (shift to the left by $$\frac{\pi}{3}$$).
6. **Vertical shift:** The graph is shifted up by $$1$$ unit.
7. **Summary:**
- Amplitude: $$3$$
- Period: $$\pi$$
- Phase shift: left $$\frac{\pi}{3}$$
- Vertical shift: up $$1$$
This function oscillates between $$1-3= -2$$ and $$1+3=4$$ with period $$\pi$$ and is shifted left by $$\frac{\pi}{3}$$.