Subjects trigonometry

Streetlight Angle Daca1A

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Question: Consider the following figure. FIGURE 3 ft 4 1/2 ft 2.1 ft \theta Figure Description Determine the angle $\theta$ (in degrees) in the design of the streetlight shown in the figure, where the height is $2.1$ ft. (Round your answer to one decimal place.) $\theta = \degree$
1. **Problem Statement:** We need to find the angle $\theta$ formed between the vertical pole and the upper arm of the streetlight. 2. **Given:** - Height of the pole (vertical side) = $2.1$ ft - Length of the upper arm (hypotenuse) = $3$ ft - Length of the lower diagonal support = $4 \frac{1}{2} = 4.5$ ft (not directly needed for $\theta$) 3. **Formula:** To find angle $\theta$ in a right triangle, use the cosine function: $$\cos(\theta) = \frac{\text{adjacent side}}{\text{hypotenuse}}$$ Here, the adjacent side to $\theta$ is the vertical pole height $2.1$ ft, and the hypotenuse is the upper arm $3$ ft. 4. **Calculate cosine of $\theta$:** $$\cos(\theta) = \frac{2.1}{3}$$ 5. **Simplify the fraction:** $$\cos(\theta) = \frac{\cancel{2.1}}{\cancel{3}} = 0.7$$ 6. **Find $\theta$ by taking the inverse cosine (arccos):** $$\theta = \cos^{-1}(0.7)$$ 7. **Calculate $\theta$ using a calculator:** $$\theta \approx 45.57^\circ$$ 8. **Round to one decimal place:** $$\theta \approx 45.6^\circ$$ **Final answer:** $$\boxed{\theta = 45.6^\circ}$$
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