Question: Introduce and apply identities
• $\tan\theta = \frac{\sin\theta}{\cos\theta}$
• $\sin^2 \theta + \cos^2 \theta = 1$
• $1 + \tan^2 \theta = \sec^2 \theta$
• $1 + \cot^2 \theta = \csc^2 \theta$
Create a classwork with problems involving the above subtopic also involve the ones of reduction formulas of 180 and 360 only
1. **State the problem:** Use the given trigonometric identities and reduction formulas to solve problems.
2. **Recall the identities:**
- $\tan\theta = \frac{\sin\theta}{\cos\theta}$
- $\sin^2 \theta + \cos^2 \theta = 1$
- $1 + \tan^2 \theta = \sec^2 \theta$
- $1 + \cot^2 \theta = \csc^2 \theta$
3. **Reduction formulas for angles:**
- $\sin(180^\circ - \theta) = \sin\theta$
- $\cos(180^\circ - \theta) = -\cos\theta$
- $\tan(180^\circ - \theta) = -\tan\theta$
- $\sin(360^\circ - \theta) = -\sin\theta$
- $\cos(360^\circ - \theta) = \cos\theta$
- $\tan(360^\circ - \theta) = -\tan\theta$
4. **Problem 1:** Simplify $\tan(180^\circ - \theta)$ using identities.
Using the reduction formula:
$$\tan(180^\circ - \theta) = -\tan\theta$$
Using the identity $\tan\theta = \frac{\sin\theta}{\cos\theta}$, this becomes:
$$\tan(180^\circ - \theta) = -\frac{\sin\theta}{\cos\theta}$$
5. **Problem 2:** Verify $\sin^2(180^\circ - \theta) + \cos^2(180^\circ - \theta) = 1$
Using reduction formulas:
$$\sin(180^\circ - \theta) = \sin\theta$$
$$\cos(180^\circ - \theta) = -\cos\theta$$
Then:
$$\sin^2(180^\circ - \theta) + \cos^2(180^\circ - \theta) = \sin^2\theta + (-\cos\theta)^2 = \sin^2\theta + \cos^2\theta = 1$$
6. **Problem 3:** Simplify $1 + \tan^2(360^\circ - \theta)$
Using reduction formula:
$$\tan(360^\circ - \theta) = -\tan\theta$$
Then:
$$1 + \tan^2(360^\circ - \theta) = 1 + (-\tan\theta)^2 = 1 + \tan^2\theta = \sec^2\theta$$
7. **Summary:** These problems show how to apply the fundamental identities and reduction formulas for angles $180^\circ$ and $360^\circ$ to simplify and verify trigonometric expressions.
**Final answers:**
- $\tan(180^\circ - \theta) = -\tan\theta$
- $\sin^2(180^\circ - \theta) + \cos^2(180^\circ - \theta) = 1$
- $1 + \tan^2(360^\circ - \theta) = \sec^2\theta$