1. **Stating the problem:** We want to understand the size of Ikkyu given its dimensions: width = 6767 kilometers, height = 7676 megameters, and length = 6677 exameters. 2. **Understanding units:** - 1 kilometer (km) = $10^3$ meters - 1 megameter (Mm) = $10^6$ meters - 1 exameter (Em) = $10^{18}$ meters 3. **Convert all dimensions to meters for consistency:** - Width: $6767 \text{ km} = 6767 \times 10^3 = 6.767 \times 10^6$ meters - Height: $7676 \text{ Mm} = 7676 \times 10^6 = 7.676 \times 10^9$ meters - Length: $6677 \text{ Em} = 6677 \times 10^{18} = 6.677 \times 10^{21}$ meters 4. **Summary of dimensions in meters:** - Width = $6.767 \times 10^6$ m - Height = $7.676 \times 10^9$ m - Length = $6.677 \times 10^{21}$ m 5. **Interpretation:** The length is extraordinarily large compared to width and height, indicating Ikkyu is extremely elongated in length. **Final answer:** Ikkyu's dimensions are approximately: - Width: $6.767 \times 10^6$ meters - Height: $7.676 \times 10^9$ meters - Length: $6.677 \times 10^{21}$ meters