Subjects fractions

Sum Shaded Areas F261A2

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Question: User: Left circle: a circle divided into 8 equal sectors with 5 sectors shaded gray, position_hint \in \{top-left\}.\n\nMiddle circle: a circle divided into 6 equal sectors with 1 sector shaded gray at the bottom, position_hint \in \{center\}.\n\nRight circle: a circle divided into 7 equal sectors with 3 sectors shaded gray in the lower-right/lower region, position_hint \in \{top-right\}.\n\nWhat is the sum of the shaded areas in the three circles above if each\ncircle represents one whole?
1. **State the problem:**\nWe have three circles, each representing one whole (1).\n- Left circle: divided into 8 equal sectors, 5 shaded.\n- Middle circle: divided into 6 equal sectors, 1 shaded.\n- Right circle: divided into 7 equal sectors, 3 shaded.\nWe want to find the sum of the shaded areas from all three circles.\n\n2. **Formula and rules:**\nEach shaded area is a fraction of the whole circle. The fraction is given by \n$$\text{shaded fraction} = \frac{\text{number of shaded sectors}}{\text{total sectors}}.$$\nThe total shaded area sum is the sum of these fractions.\n\n3. **Calculate each shaded fraction:**\n- Left circle shaded fraction: $$\frac{5}{8}.$$\n- Middle circle shaded fraction: $$\frac{1}{6}.$$\n- Right circle shaded fraction: $$\frac{3}{7}.$$\n\n4. **Sum the shaded fractions:**\n$$\frac{5}{8} + \frac{1}{6} + \frac{3}{7}.$$\n\n5. **Find common denominator:**\nThe denominators are 8, 6, and 7.\nThe least common multiple (LCM) of 8, 6, and 7 is 168.\n\n6. **Convert each fraction to denominator 168:**\n$$\frac{5}{8} = \frac{5 \times 21}{8 \times 21} = \frac{105}{168},$$\n$$\frac{1}{6} = \frac{1 \times 28}{6 \times 28} = \frac{28}{168},$$\n$$\frac{3}{7} = \frac{3 \times 24}{7 \times 24} = \frac{72}{168}.$$\n\n7. **Add the fractions:**\n$$\frac{105}{168} + \frac{28}{168} + \frac{72}{168} = \frac{105 + 28 + 72}{168} = \frac{205}{168}.$$\n\n8. **Simplify the fraction if possible:**\n205 and 168 share no common factors other than 1, so the fraction is in simplest form.\n\n9. **Convert to mixed number:**\n$$\frac{205}{168} = 1 + \frac{37}{168}.$$\n\n**Final answer:**\nThe sum of the shaded areas is $$\frac{205}{168}$$ or $$1 \frac{37}{168}.$$